Operator

&>>=(_:_:)

Calculates the result of shifting a value’s binary representation the specified number of digits to the right, masking the shift amount to the type’s bit width, and stores the result in the left-hand-side variable.

Required. Default implementation provided.

Declaration

static func &>>= (lhs: inout Self, rhs: Self)

Parameters

lhs

The value to shift.

rhs

The number of bits to shift lhs to the right. If rhs is outside the range 0..<lhs.bitWidth, it is masked to produce a value within that range.

Discussion

The &>>= operator performs a masking shift, where the value passed as rhs is masked to produce a value in the range 0..<lhs.bitWidth. The shift is performed using this masked value.

The following example defines x as an instance of UInt8, an 8-bit, unsigned integer type. If you use 2 as the right-hand-side value in an operation on x, the shift amount requires no masking.

var x: UInt8 = 30                 // 0b00011110
x &>>= 2
// x == 7                         // 0b00000111

However, if you use 19 as rhs, the operation first bitmasks rhs to 3, and then uses that masked value as the number of bits to shift lhs.

var y: UInt8 = 30                 // 0b00011110
y &>>= 19
// y == 3                         // 0b00000011

Default Implementations

FixedWidthInteger Implementations

static func &>>= <Other>(inout Self, Other)

Calculates the result of shifting a value’s binary representation the specified number of digits to the right, masking the shift amount to the type’s bit width, and stores the result in the left-hand-side variable.